Solve {r}{15*3-4-1+5*8-12.0:2+4+1}{45-4+1+5*8-120:2+4+1}

$$\left. \begin{array} { r } { 15 \times 3 - 4 - 1 + 5 \times 8 - 12.0 : 2 + 4 + 1 } \\ { 45 - 4 + 1 + 5 \times 8 - 120 : 2 + 4 + 1 } \end{array} \right.$$

Sort

$$27,79$$

Solution Steps

Multiply 15 and 3 to get 45. Multiply 5 and 8 to get 40.

$$sort(45-4-1+40-\frac{12}{2}+4+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Subtract 4 from 45 to get 41.

$$sort(41-1+40-\frac{12}{2}+4+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Subtract 1 from 41 to get 40.

$$sort(40+40-\frac{12}{2}+4+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Add 40 and 40 to get 80.

$$sort(80-\frac{12}{2}+4+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Divide 12 by 2 to get 6.

$$sort(80-6+4+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Subtract 6 from 80 to get 74.

$$sort(74+4+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Add 74 and 4 to get 78.

$$sort(78+1,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Add 78 and 1 to get 79.

$$sort(79,45-4+1+5\times 8-\frac{120}{2}+4+1)$$

Subtract 4 from 45 to get 41.

$$sort(79,41+1+5\times 8-\frac{120}{2}+4+1)$$

Add 41 and 1 to get 42.

$$sort(79,42+5\times 8-\frac{120}{2}+4+1)$$

Multiply 5 and 8 to get 40.

$$sort(79,42+40-\frac{120}{2}+4+1)$$

Add 42 and 40 to get 82.

$$sort(79,82-\frac{120}{2}+4+1)$$

Divide 120 by 2 to get 60.

$$sort(79,82-60+4+1)$$

Subtract 60 from 82 to get 22.

$$sort(79,22+4+1)$$

Add 22 and 4 to get 26.

$$sort(79,26+1)$$

Add 26 and 1 to get 27.

$$sort(79,27)$$

To sort the list, start from a single element 79.

$$79$$

Insert 27 to the appropriate location in the new list.

$$27,79$$

Evaluate

$$79,\ 27$$