Solve {r}{141}{121}{23-2}{06-2}

$$\left. \begin{array} { r } { 141 } \\ { 121 } \\ { 23 - 2 } \\ { 06 - 2 } \end{array} \right.$$

Sort

$$4,21,121,141$$

Solution Steps

Subtract 2 from 23 to get 21.

$$sort(141,121,21,6-2)$$

Subtract 2 from 6 to get 4.

$$sort(141,121,21,4)$$

To sort the list, start from a single element 141.

$$141$$

Insert 121 to the appropriate location in the new list.

$$121,141$$

Insert 21 to the appropriate location in the new list.

$$21,121,141$$

Insert 4 to the appropriate location in the new list.

$$4,21,121,141$$

Evaluate

$$141,\ 121,\ 21,\ 4$$