Solve {r}{(1/3)^{8}+8*(2/3)(1/3)^{7}+8!/6!2!(frac{2}{3})^{2}(frac{1}{3})^{6}+frac{8!}{5!3!}(frac{2}{3})^{3}(frac{1}{3})^{5}+frac{8!}{4!4!}(frac{2}{3})^4(frac{1}{3})^4}{quad+frac{8!}{3!5!}(frac{2}{3})^5(frac{1}{3})^3}

$$\left. \begin{array} { r } { ( \frac { 1 } { 3 } ) ^ { 8 } + 8 \cdot ( \frac { 2 } { 3 } ) ( \frac { 1 } { 3 } ) ^ { 7 } + \frac { 8 ! } { 6 ! 2 ! } ( \frac { 2 } { 3 } ) ^ { 2 } ( \frac { 1 } { 3 } ) ^ { 6 } + \frac { 8 ! } { 5 ! 3 ! } ( \frac { 2 } { 3 } ) ^ { 3 } ( \frac { 1 } { 3 } ) ^ { 5 } + \frac { 8 ! } { 4 ! 4 ! } ( \frac { 2 } { 3 } ) ^ { 4 } ( \frac { 1 } { 3 } ) ^ { 4 } } \\ { \quad + \frac { 8 ! } { 3 ! 5 ! } ( \frac { 2 } { 3 } ) ^ { 5 } ( \frac { 1 } { 3 } ) ^ { 3 } } \end{array} \right.$$

Evaluate

$$\frac{1163}{2187}\approx 0.531778692$$

Solution Steps

Multiply 4! and 4! to get \left(4!\right)^{2}.

$$\left(\frac{1}{3}\right)^{8}+8\times \frac{2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{1}{3} to the power of 8 and get \frac{1}{6561}.

$$\frac{1}{6561}+8\times \frac{2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Express 8\times \frac{2}{3} as a single fraction.

$$\frac{1}{6561}+\frac{8\times 2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 8 and 2 to get 16.

$$\frac{1}{6561}+\frac{16}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{1}{3} to the power of 7 and get \frac{1}{2187}.

$$\frac{1}{6561}+\frac{16}{3}\times \frac{1}{2187}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply \frac{16}{3} times \frac{1}{2187} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{6561}+\frac{16\times 1}{3\times 2187}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Do the multiplications in the fraction \frac{16\times 1}{3\times 2187}.

$$\frac{1}{6561}+\frac{16}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Since \frac{1}{6561} and \frac{16}{6561} have the same denominator, add them by adding their numerators.

$$\frac{1+16}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Add 1 and 16 to get 17.

$$\frac{17}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 8 is 40320.

$$\frac{17}{6561}+\frac{40320}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 6 is 720.

$$\frac{17}{6561}+\frac{40320}{720\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 2 is 2.

$$\frac{17}{6561}+\frac{40320}{720\times 2}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 720 and 2 to get 1440.

$$\frac{17}{6561}+\frac{40320}{1440}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 by 1440 to get 28.

$$\frac{17}{6561}+28\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{17}{6561}+28\times \frac{4}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Express 28\times \frac{4}{9} as a single fraction.

$$\frac{17}{6561}+\frac{28\times 4}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 28 and 4 to get 112.

$$\frac{17}{6561}+\frac{112}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{1}{3} to the power of 6 and get \frac{1}{729}.

$$\frac{17}{6561}+\frac{112}{9}\times \frac{1}{729}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply \frac{112}{9} times \frac{1}{729} by multiplying numerator times numerator and denominator times denominator.

$$\frac{17}{6561}+\frac{112\times 1}{9\times 729}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Do the multiplications in the fraction \frac{112\times 1}{9\times 729}.

$$\frac{17}{6561}+\frac{112}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Since \frac{17}{6561} and \frac{112}{6561} have the same denominator, add them by adding their numerators.

$$\frac{17+112}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Add 17 and 112 to get 129.

$$\frac{129}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Reduce the fraction \frac{129}{6561} to lowest terms by extracting and canceling out 3.

$$\frac{43}{2187}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 8 is 40320.

$$\frac{43}{2187}+\frac{40320}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 5 is 120.

$$\frac{43}{2187}+\frac{40320}{120\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 3 is 6.

$$\frac{43}{2187}+\frac{40320}{120\times 6}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 120 and 6 to get 720.

$$\frac{43}{2187}+\frac{40320}{720}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 by 720 to get 56.

$$\frac{43}{2187}+56\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{2}{3} to the power of 3 and get \frac{8}{27}.

$$\frac{43}{2187}+56\times \frac{8}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Express 56\times \frac{8}{27} as a single fraction.

$$\frac{43}{2187}+\frac{56\times 8}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 56 and 8 to get 448.

$$\frac{43}{2187}+\frac{448}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{1}{3} to the power of 5 and get \frac{1}{243}.

$$\frac{43}{2187}+\frac{448}{27}\times \frac{1}{243}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply \frac{448}{27} times \frac{1}{243} by multiplying numerator times numerator and denominator times denominator.

$$\frac{43}{2187}+\frac{448\times 1}{27\times 243}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Do the multiplications in the fraction \frac{448\times 1}{27\times 243}.

$$\frac{43}{2187}+\frac{448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Least common multiple of 2187 and 6561 is 6561. Convert \frac{43}{2187} and \frac{448}{6561} to fractions with denominator 6561.

$$\frac{129}{6561}+\frac{448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Since \frac{129}{6561} and \frac{448}{6561} have the same denominator, add them by adding their numerators.

$$\frac{129+448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Add 129 and 448 to get 577.

$$\frac{577}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 8 is 40320.

$$\frac{577}{6561}+\frac{40320}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 4 is 24.

$$\frac{577}{6561}+\frac{40320}{24^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate 24 to the power of 2 and get 576.

$$\frac{577}{6561}+\frac{40320}{576}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 by 576 to get 70.

$$\frac{577}{6561}+70\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{2}{3} to the power of 4 and get \frac{16}{81}.

$$\frac{577}{6561}+70\times \frac{16}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Express 70\times \frac{16}{81} as a single fraction.

$$\frac{577}{6561}+\frac{70\times 16}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 70 and 16 to get 1120.

$$\frac{577}{6561}+\frac{1120}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{1}{3} to the power of 4 and get \frac{1}{81}.

$$\frac{577}{6561}+\frac{1120}{81}\times \frac{1}{81}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply \frac{1120}{81} times \frac{1}{81} by multiplying numerator times numerator and denominator times denominator.

$$\frac{577}{6561}+\frac{1120\times 1}{81\times 81}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Do the multiplications in the fraction \frac{1120\times 1}{81\times 81}.

$$\frac{577}{6561}+\frac{1120}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Since \frac{577}{6561} and \frac{1120}{6561} have the same denominator, add them by adding their numerators.

$$\frac{577+1120}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Add 577 and 1120 to get 1697.

$$\frac{1697}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 8 is 40320.

$$\frac{1697}{6561}+\frac{40320}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 3 is 6.

$$\frac{1697}{6561}+\frac{40320}{6\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

The factorial of 5 is 120.

$$\frac{1697}{6561}+\frac{40320}{6\times 120}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 6 and 120 to get 720.

$$\frac{1697}{6561}+\frac{40320}{720}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 by 720 to get 56.

$$\frac{1697}{6561}+56\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{2}{3} to the power of 5 and get \frac{32}{243}.

$$\frac{1697}{6561}+56\times \frac{32}{243}\times \left(\frac{1}{3}\right)^{3}$$

Express 56\times \frac{32}{243} as a single fraction.

$$\frac{1697}{6561}+\frac{56\times 32}{243}\times \left(\frac{1}{3}\right)^{3}$$

Multiply 56 and 32 to get 1792.

$$\frac{1697}{6561}+\frac{1792}{243}\times \left(\frac{1}{3}\right)^{3}$$

Calculate \frac{1}{3} to the power of 3 and get \frac{1}{27}.

$$\frac{1697}{6561}+\frac{1792}{243}\times \frac{1}{27}$$

Multiply \frac{1792}{243} times \frac{1}{27} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1697}{6561}+\frac{1792\times 1}{243\times 27}$$

Do the multiplications in the fraction \frac{1792\times 1}{243\times 27}.

$$\frac{1697}{6561}+\frac{1792}{6561}$$

Since \frac{1697}{6561} and \frac{1792}{6561} have the same denominator, add them by adding their numerators.

$$\frac{1697+1792}{6561}$$

Add 1697 and 1792 to get 3489.

$$\frac{3489}{6561}$$

Reduce the fraction \frac{3489}{6561} to lowest terms by extracting and canceling out 3.

$$\frac{1163}{2187}$$

Factor

$$\frac{1163}{3 ^ {7}} = 0.5317786922725194$$