Solve {r}{8-10/10}{7-4/7}

$$\left. \begin{array} { r } { \frac { 8 - 10 } { 10 } } \\ { \frac { 7 - 4 } { 7 } } \end{array} \right.$$

Sort

$$-\frac{1}{5},\ \frac{3}{7}$$

Solution Steps

Subtract 10 from 8 to get -2.

$$sort(\frac{-2}{10},\frac{7-4}{7})$$

Reduce the fraction \frac{-2}{10} to lowest terms by extracting and canceling out 2.

$$sort(-\frac{1}{5},\frac{7-4}{7})$$

Subtract 4 from 7 to get 3.

$$sort(-\frac{1}{5},\frac{3}{7})$$

Least common denominator of the numbers in the list -\frac{1}{5},\frac{3}{7} is 35. Convert numbers in the list to fractions with denominator 35.

$$-\frac{7}{35},\frac{15}{35}$$

Evaluate

$$-\frac{1}{5},\ \frac{3}{7}$$