Solve for y, x

x=2<br/>y=-8

$x=2$

$y=−8$

$y=−8$

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y=2^{3}-12\times 2+8

Consider the first equation. Insert the known values of variables into the equation.

y=8-12\times 2+8

Calculate 2 to the power of 3 and get 8.

y=8-24+8

Multiply -12 and 2 to get -24.

y=-16+8

Subtract 24 from 8 to get -16.

y=-8

Add -16 and 8 to get -8.

y=-8 x=2

The system is now solved.

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