Solve {l}{y=2a+8}{16=8a+3}

$$\left. \begin{array} { l } { y = 2 a + 8 } \\ { 16 = 8 a + 3 } \end{array} \right.$$

Solve for y, a

$$y = \frac{45}{4} = 11\frac{1}{4} = 11.25$$

$$a = \frac{13}{8} = 1\frac{5}{8} = 1.625$$

Solution Steps

Consider the second equation. Swap sides so that all variable terms are on the left hand side.

$$8a+3=16$$

Subtract 3 from both sides.

$$8a=16-3$$

Subtract 3 from 16 to get 13.

$$8a=13$$

Divide both sides by 8.

$$a=\frac{13}{8}$$

Consider the first equation. Insert the known values of variables into the equation.

$$y=2\times \frac{13}{8}+8$$

Multiply 2 and \frac{13}{8} to get \frac{13}{4}.

$$y=\frac{13}{4}+8$$

Add \frac{13}{4} and 8 to get \frac{45}{4}.

$$y=\frac{45}{4}$$

The system is now solved.

$$y=\frac{45}{4} a=\frac{13}{8}$$