Solve {l}{x-4x+4y-16=60}{60-4x+240-16=60}

$$\left. \begin{array} { l } { x - 4 x + 4 y - 16 = 60 } \\ { 60 - 4 x + 240 - 16 = 60 } \end{array} \right.$$

Solve for x, y

$$x=56$$

$$y=61$$

Solution Steps

Consider the second equation. Add 60 and 240 to get 300.

$$300-4x-16=60$$

Subtract 16 from 300 to get 284.

$$284-4x=60$$

Subtract 284 from both sides.

$$-4x=60-284$$

Subtract 284 from 60 to get -224.

$$-4x=-224$$

Divide both sides by -4.

$$x=\frac{-224}{-4}$$

Divide -224 by -4 to get 56.

$$x=56$$

Consider the first equation. Insert the known values of variables into the equation.

$$56-4\times 56+4y-16=60$$

Multiply -4 and 56 to get -224.

$$56-224+4y-16=60$$

Subtract 224 from 56 to get -168.

$$-168+4y-16=60$$

Subtract 16 from -168 to get -184.

$$-184+4y=60$$

Add 184 to both sides.

$$4y=60+184$$

Add 60 and 184 to get 244.

$$4y=244$$

Divide both sides by 4.

$$y=\frac{244}{4}$$

Divide 244 by 4 to get 61.

$$y=61$$

The system is now solved.

$$x=56 y=61$$