Solve {l}{x^3-3x^2}{+1-(1/x)}

$$\left. \begin{array} { l } { x ^ { 3 } - 3 x ^ { 2 } } \\ { + 1 - ( \frac { 1 } { x } ) } \end{array} \right.$$

Evaluate

$$\frac{x^{4}-3x^{3}+x-1}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{3}-3x^{2}+1 times \frac{x}{x}.

$$\frac{\left(x^{3}-3x^{2}+1\right)x}{x}-\frac{1}{x}$$

Since \frac{\left(x^{3}-3x^{2}+1\right)x}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(x^{3}-3x^{2}+1\right)x-1}{x}$$

Do the multiplications in \left(x^{3}-3x^{2}+1\right)x-1.

$$\frac{x^{4}-3x^{3}+x-1}{x}$$

Factor

$$\frac{x^{4}-3x^{3}+x-1}{x}$$