Solve {l}{5x=6}{text{Solvefor}ytext{where}}{y=x^3+4x^2}

$$\left. \begin{array} { l } { 5 x = 6 }\\ { \text{Solve for } y \text{ where} } \\ { y = x ^ {3} + 4 x ^ {2} } \end{array} \right.$$

Solve for x, y

$$y = \frac{936}{125} = 7\frac{61}{125} = 7.488$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$x=\frac{6}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(\frac{6}{5}\right)^{3}+4\times \left(\frac{6}{5}\right)^{2}$$

Calculate \frac{6}{5} to the power of 3 and get \frac{216}{125}.

$$y=\frac{216}{125}+4\times \left(\frac{6}{5}\right)^{2}$$

Calculate \frac{6}{5} to the power of 2 and get \frac{36}{25}.

$$y=\frac{216}{125}+4\times \frac{36}{25}$$

Multiply 4 and \frac{36}{25} to get \frac{144}{25}.

$$y=\frac{216}{125}+\frac{144}{25}$$

Add \frac{216}{125} and \frac{144}{25} to get \frac{936}{125}.

$$y=\frac{936}{125}$$

The system is now solved.

$$x=\frac{6}{5} y=\frac{936}{125}$$