Solve {l}{-3=x}{text{Solvefor}ytext{where}}{y=x^2-1+2x^2}

$$\left. \begin{array} { l } { -3 = x }\\ { \text{Solve for } y \text{ where} } \\ { y = x ^ {2} - 1 + 2 x ^ {2} } \end{array} \right.$$

Solve for x, y

$$y=26$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$x=-3$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(-3\right)^{2}-1+2\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$y=9-1+2\left(-3\right)^{2}$$

Subtract 1 from 9 to get 8.

$$y=8+2\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$y=8+2\times 9$$

Multiply 2 and 9 to get 18.

$$y=8+18$$

Add 8 and 18 to get 26.

$$y=26$$

The system is now solved.

$$x=-3 y=26$$