Solve for x, y
x=3
y=7
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3^{2}+y=16
Consider the first equation. Insert the known values of variables into the equation.
9+y=16
Calculate 3 to the power of 2 and get 9.
y=16-9
Subtract 9 from both sides.
y=7
Subtract 9 from 16 to get 7.
x=3 y=7
The system is now solved.
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