Solve for x, y
x=6-y_{2}
y=-\frac{\left(6-y_{2}\right)^{2}}{2}
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x+y_{2}=6,x^{2}+2y=0
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
x+y_{2}=6
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
x=6-y_{2}
Subtract y_{2} from both sides of the equation.
\left(6-y_{2}\right)^{2}+2y=0
Substitute -y_{2}+6 for x in the other equation, x^{2}+2y=0.
2y=-\left(6-y_{2}\right)^{2}
Subtract \left(-y_{2}+6\right)^{2} from both sides of the equation.
y=-\frac{\left(6-y_{2}\right)^{2}}{2}
Divide both sides by 2.
x=6-y_{2},y=-\frac{\left(6-y_{2}\right)^{2}}{2}
The system is now solved.
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