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4\times 3+3y=9
Consider the second equation. Insert the known values of variables into the equation.
12+3y=9
Multiply 4 and 3 to get 12.
3y=9-12
Subtract 12 from both sides.
3y=-3
Subtract 12 from 9 to get -3.
y=\frac{-3}{3}
Divide both sides by 3.
y=-1
Divide -3 by 3 to get -1.
x=3 y=-1
The system is now solved.