Solve {l}{x+y=1700}{15x+20y=65}

$$\left. \begin{array} { l } { x + y = 1700 } \\ { 15 x + 20 y = 65 } \end{array} \right.$$

Solve for x, y

$$x=6787$$

$$y=-5087$$

Steps Using Substitution

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$$x+y=1700,15x+20y=65$$

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

$$x+y=1700$$

Subtract y from both sides of the equation.

$$x=-y+1700$$

Substitute -y+1700 for x in the other equation, 15x+20y=65.

$$15\left(-y+1700\right)+20y=65$$

Multiply 15 times -y+1700.

$$-15y+25500+20y=65$$

Add -15y to 20y.

$$5y+25500=65$$

Subtract 25500 from both sides of the equation.

$$5y=-25435$$

Divide both sides by 5.

$$y=-5087$$

Substitute -5087 for y in x=-y+1700. Because the resulting equation contains only one variable, you can solve for x directly.

$$x=-\left(-5087\right)+1700$$

Multiply -1 times -5087.

$$x=5087+1700$$

Add 1700 to 5087.

$$x=6787$$

The system is now solved.

$$x=6787,y=-5087$$

Steps Using Matrices

Put the equations in standard form and then use matrices to solve the system of equations.

$$x+y=1700,15x+20y=65$$

Write the equations in matrix form.

$$\left(\begin{matrix}1&1\\15&20\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}1700\\65\end{matrix}\right)$$

Left multiply the equation by the inverse matrix of \left(\begin{matrix}1&1\\15&20\end{matrix}\right).

$$inverse(\left(\begin{matrix}1&1\\15&20\end{matrix}\right))\left(\begin{matrix}1&1\\15&20\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\15&20\end{matrix}\right))\left(\begin{matrix}1700\\65\end{matrix}\right)$$

The product of a matrix and its inverse is the identity matrix.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\15&20\end{matrix}\right))\left(\begin{matrix}1700\\65\end{matrix}\right)$$

Multiply the matrices on the left hand side of the equal sign.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\15&20\end{matrix}\right))\left(\begin{matrix}1700\\65\end{matrix}\right)$$

For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the inverse matrix is \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right), so the matrix equation can be rewritten as a matrix multiplication problem.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{20}{20-15}&-\frac{1}{20-15}\\-\frac{15}{20-15}&\frac{1}{20-15}\end{matrix}\right)\left(\begin{matrix}1700\\65\end{matrix}\right)$$

Do the arithmetic.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}4&-\frac{1}{5}\\-3&\frac{1}{5}\end{matrix}\right)\left(\begin{matrix}1700\\65\end{matrix}\right)$$

Multiply the matrices.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}4\times 1700-\frac{1}{5}\times 65\\-3\times 1700+\frac{1}{5}\times 65\end{matrix}\right)$$

Do the arithmetic.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}6787\\-5087\end{matrix}\right)$$

Extract the matrix elements x and y.

$$x=6787,y=-5087$$

Steps Using Elimination

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

$$x+y=1700,15x+20y=65$$

To make x and 15x equal, multiply all terms on each side of the first equation by 15 and all terms on each side of the second by 1.

$$15x+15y=15\times 1700,15x+20y=65$$

Simplify.

$$15x+15y=25500,15x+20y=65$$

Subtract 15x+20y=65 from 15x+15y=25500 by subtracting like terms on each side of the equal sign.

$$15x-15x+15y-20y=25500-65$$

Add 15x to -15x. Terms 15x and -15x cancel out, leaving an equation with only one variable that can be solved.

$$15y-20y=25500-65$$

Add 15y to -20y.

$$-5y=25500-65$$

Add 25500 to -65.

$$-5y=25435$$

Divide both sides by -5.

$$y=-5087$$

Substitute -5087 for y in 15x+20y=65. Because the resulting equation contains only one variable, you can solve for x directly.

$$15x+20\left(-5087\right)=65$$

Multiply 20 times -5087.

$$15x-101740=65$$

Add 101740 to both sides of the equation.

$$15x=101805$$

Divide both sides by 15.

$$x=6787$$

The system is now solved.

$$x=6787,y=-5087$$