Solve for x, y, h
x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333
y = -\frac{10}{3} = -3\frac{1}{3} \approx -3.333333333
h=0
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x=-y-2
Solve x+y=-2 for x.
2\left(-y-2\right)-y=6 5\left(-y-2\right)+2y=h
Substitute -y-2 for x in the second and third equation.
y=-\frac{10}{3} h=-3y-10
Solve these equations for y and h respectively.
h=-3\left(-\frac{10}{3}\right)-10
Substitute -\frac{10}{3} for y in the equation h=-3y-10.
h=0
Calculate h from h=-3\left(-\frac{10}{3}\right)-10.
x=-\left(-\frac{10}{3}\right)-2
Substitute -\frac{10}{3} for y in the equation x=-y-2.
x=\frac{4}{3}
Calculate x from x=-\left(-\frac{10}{3}\right)-2.
x=\frac{4}{3} y=-\frac{10}{3} h=0
The system is now solved.
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