Solve for x, y, z
x=2
y=2
z=-2
Share
Copied to clipboard
x=-y-z+2
Solve x+y+z=2 for x.
-y-z+2-y+z=-2 -y-z+2-z=y+2
Substitute -y-z+2 for x in the second and third equation.
y=2 z=-y
Solve these equations for y and z respectively.
z=-2
Substitute 2 for y in the equation z=-y.
x=-2-\left(-2\right)+2
Substitute 2 for y and -2 for z in the equation x=-y-z+2.
x=2
Calculate x from x=-2-\left(-2\right)+2.
x=2 y=2 z=-2
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}