Solve {l}{x+4=3}{6x-5y=43}

$$\left. \begin{array} { l } { x + 4 = 3 } \\ { 6 x - 5 y = 43 } \end{array} \right.$$

Solve for x, y

$$x=-1$$

$$y = -\frac{49}{5} = -9\frac{4}{5} = -9.8$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$x=3-4$$

Subtract 4 from 3 to get -1.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$6\left(-1\right)-5y=43$$

Multiply 6 and -1 to get -6.

$$-6-5y=43$$

Add 6 to both sides.

$$-5y=43+6$$

Add 43 and 6 to get 49.

$$-5y=49$$

Divide both sides by -5.

$$y=-\frac{49}{5}$$

The system is now solved.

$$x=-1 y=-\frac{49}{5}$$