Solve {l}{x+2y=3}{2y+y=4}

$$\left. \begin{array} { l } { x + 2 y = 3 } \\ { 2 y + y = 4 } \end{array} \right.$$

Solve for x, y

$$x=\frac{1}{3}\approx 0.333333333$$

$$y = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

Solution Steps

Consider the second equation. Combine 2y and y to get 3y.

$$3y=4$$

Divide both sides by 3.

$$y=\frac{4}{3}$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+2\times \frac{4}{3}=3$$

Multiply 2 and \frac{4}{3} to get \frac{8}{3}.

$$x+\frac{8}{3}=3$$

Subtract \frac{8}{3} from both sides.

$$x=3-\frac{8}{3}$$

Subtract \frac{8}{3} from 3 to get \frac{1}{3}.

$$x=\frac{1}{3}$$

The system is now solved.

$$x=\frac{1}{3} y=\frac{4}{3}$$