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x+\sqrt{2\times 14}=6
Consider the first equation. Insert the known values of variables into the equation.
x+\sqrt{28}=6
Multiply 2 and 14 to get 28.
x+2\sqrt{7}=6
Factor 28=2^{2}\times 7. Rewrite the square root of the product \sqrt{2^{2}\times 7} as the product of square roots \sqrt{2^{2}}\sqrt{7}. Take the square root of 2^{2}.
x=6-2\sqrt{7}
Subtract 2\sqrt{7} from both sides.
x=6-2\sqrt{7} y=14
The system is now solved.