Solve {l}{-r+1=0}{text{Solvefor}stext{where}}{s=r^3-r^2}

$$\left. \begin{array} { l } { -r + 1 = 0 }\\ { \text{Solve for } s \text{ where} } \\ { s = r ^ {3} - r ^ {2} } \end{array} \right.$$

Solve for r, s

$$s=0$$

Solution Steps

Consider the first equation. Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-r=-1$$

Divide both sides by -1.

$$r=\frac{-1}{-1}$$

Divide -1 by -1 to get 1.

$$r=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$s=1^{3}-1^{2}$$

Calculate 1 to the power of 3 and get 1.

$$s=1-1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$s=1-1$$

Subtract 1 from 1 to get 0.

$$s=0$$

The system is now solved.

$$r=1 s=0$$