Solve {l}{k=a-(3b+c)^2}{b=-0.7}{a=1.4}{c=0.5}

$$\left. \begin{array} { l } { k = a - ( 3 b + c ) ^ { 2 } } \\ { b = - 0.7 } \\ { a = 1.4 } \\ { c = 0.5 } \end{array} \right.$$

Solve for k, a, b, c

$$k=-1.16$$

$$a=1.4$$

$$b=-0.7$$

$$c=0.5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$k=1.4-\left(3\left(-0.7\right)+0.5\right)^{2}$$

Multiply 3 and -0.7 to get -2.1.

$$k=1.4-\left(-2.1+0.5\right)^{2}$$

Add -2.1 and 0.5 to get -1.6.

$$k=1.4-\left(-1.6\right)^{2}$$

Calculate -1.6 to the power of 2 and get 2.56.

$$k=1.4-2.56$$

Subtract 2.56 from 1.4 to get -1.16.

$$k=-1.16$$

The system is now solved.

$$k=-1.16 a=1.4 b=-0.7 c=0.5$$