Solve {l}{b=1}{-4/3k+b=1/3}

$$\left. \begin{array} { l } { b = 1 } \\ { - \frac { 4 } { 3 } k + b = \frac { 1 } { 3 } } \end{array} \right.$$

Solve for b, k

$$b=1$$

$$k=\frac{1}{2}=0.5$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$-\frac{4}{3}k+1=\frac{1}{3}$$

Subtract 1 from both sides.

$$-\frac{4}{3}k=\frac{1}{3}-1$$

Subtract 1 from \frac{1}{3} to get -\frac{2}{3}.

$$-\frac{4}{3}k=-\frac{2}{3}$$

Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}.

$$k=-\frac{2}{3}\left(-\frac{3}{4}\right)$$

Multiply -\frac{2}{3} and -\frac{3}{4} to get \frac{1}{2}.

$$k=\frac{1}{2}$$

The system is now solved.

$$b=1 k=\frac{1}{2}$$