Solve {l}{ab^2-3ab-5a}{b+b-3*0*b-5}

$$\left. \begin{array} { l } { a b ^ { 2 } - 3 a b - 5 a } \\ { b + b - 3 \cdot 0 \cdot b - 5 } \end{array} \right.$$

Least Common Multiple

$$a\left(2b-5\right)\left(b^{2}-3b-5\right)$$

Solution Steps

Factor the expressions that are not already factored.

$$a\left(b^{2}-3b-5\right)=a\left(b-\left(-\frac{1}{2}\sqrt{29}+\frac{3}{2}\right)\right)\left(b-\left(\frac{1}{2}\sqrt{29}+\frac{3}{2}\right)\right)$$

Identify all the factors and their highest power in all expressions. Multiply the highest powers of these factors to get the least common multiple.

$$a\left(2b-5\right)\left(b^{2}-3b-5\right)$$

Expand the expression.

$$2ab^{3}-11ab^{2}+5ab+25a$$

Evaluate

$$a\left(b^{2}-3b-5\right),\ 2b-5$$