Solve {l}{R=8x+6y}{text{en}y=2text{and}R=16}

$$\left. \begin{array} { l } { R = 8 x + 6 y } \\ { \text { en } y = 2 \text { and } R = 16 } \end{array} \right.$$

Solve for R, x, y

$$x=\frac{1}{2}=0.5$$

$$y=2$$

$$R=16$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$16=8x+6\times 2$$

Multiply 6 and 2 to get 12.

$$16=8x+12$$

Swap sides so that all variable terms are on the left hand side.

$$8x+12=16$$

Subtract 12 from both sides.

$$8x=16-12$$

Subtract 12 from 16 to get 4.

$$8x=4$$

Divide both sides by 8.

$$x=\frac{4}{8}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{1}{2}$$

The system is now solved.

$$R=16 x=\frac{1}{2} y=2$$