Solve {l}{H_{7}=70.29-60*0.002+60*0.003=}{H_{8}=70.29-60*0.002+60*0.003=}{H_{9}=70.29-60*0.002+60*0.003=}{H_{10}=70.29-60*0.002+60*0.003=4}{H_{11}=70.29-60*0.002+60*0.003=4}{H_{12}=70.29-60*0.002+60*0.003=4}{H_{13}=70.29-60*0.002+60*0.003=4}{H_{14}=70.29-60*0.002+60*0.003=4}{H_{15}=70.29-60*0.002+60*0.003=4}{H_{16}=70.29-60*0.002+60*0.003=4}

$$\left. \begin{array} { l } { H _ { 7 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = } \\ { H _ { 8 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = } \\ { H _ { 9 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = } \\ { H _ { 10 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \\ { H _ { 11 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \\ { H _ { 12 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \\ { H _ { 13 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \\ { H _ { 14 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \\ { H _ { 15 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \\ { H _ { 16 } = 70.29 - 60 \times 0.002 + 60 \times 0.003 = 4 } \end{array} \right.$$

Solve for H_7, H_8, H_9, H_10

$$H_{7}=70.35$$

$$H_{8}=70.35$$

$$H_{9}=70.35$$

$$H_{10}=70.35$$

Solution Steps

Consider the first equation. Multiply 60 and 0.002 to get 0.12.

$$H_{7}=70.29-0.12+60\times 0.003$$

Subtract 0.12 from 70.29 to get 70.17.

$$H_{7}=70.17+60\times 0.003$$

Multiply 60 and 0.003 to get 0.18.

$$H_{7}=70.17+0.18$$

Add 70.17 and 0.18 to get 70.35.

$$H_{7}=70.35$$

Consider the second equation. Multiply 60 and 0.002 to get 0.12.

$$H_{8}=70.29-0.12+60\times 0.003$$

Subtract 0.12 from 70.29 to get 70.17.

$$H_{8}=70.17+60\times 0.003$$

Multiply 60 and 0.003 to get 0.18.

$$H_{8}=70.17+0.18$$

Add 70.17 and 0.18 to get 70.35.

$$H_{8}=70.35$$

Consider the third equation. Multiply 60 and 0.002 to get 0.12.

$$H_{9}=70.29-0.12+60\times 0.003$$

Subtract 0.12 from 70.29 to get 70.17.

$$H_{9}=70.17+60\times 0.003$$

Multiply 60 and 0.003 to get 0.18.

$$H_{9}=70.17+0.18$$

Add 70.17 and 0.18 to get 70.35.

$$H_{9}=70.35$$

Consider the fourth equation. Multiply 60 and 0.002 to get 0.12.

$$H_{10}=70.29-0.12+60\times 0.003$$

Subtract 0.12 from 70.29 to get 70.17.

$$H_{10}=70.17+60\times 0.003$$

Multiply 60 and 0.003 to get 0.18.

$$H_{10}=70.17+0.18$$

Add 70.17 and 0.18 to get 70.35.

$$H_{10}=70.35$$

The system is now solved.

$$H_{7}=70.35 H_{8}=70.35 H_{9}=70.35 H_{10}=70.35$$