Solve {l}{F-0.8*15mu-15*0-6=1.5}{15mu*0.8+15*0.6=1.5*8}

$$\left. \begin{array} { l } { F - 0.8 \times 15 \mu - 15 \times 0 - 6 = 1.5 } \\ { 15 \mu \times 0.8 + 15 \times 0.6 = 1.5 \times 8 } \end{array} \right.$$

Solve for F, μ

$$F=10.5$$

$$\mu =0.25$$

Solution Steps

Consider the second equation. Multiply 15 and 0.8 to get 12.

$$12\mu +15\times 0.6=1.5\times 8$$

Multiply 15 and 0.6 to get 9.

$$12\mu +9=1.5\times 8$$

Multiply 1.5 and 8 to get 12.

$$12\mu +9=12$$

Subtract 9 from both sides.

$$12\mu =12-9$$

Subtract 9 from 12 to get 3.

$$12\mu =3$$

Divide both sides by 12.

$$\mu =\frac{3}{12}$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\mu =\frac{1}{4}$$

Consider the first equation. Insert the known values of variables into the equation.

$$F-0.8\times 15\times \frac{1}{4}-15\times 0-6=1.5$$

Multiply 0.8 and 15 to get 12.

$$F-12\times \frac{1}{4}-15\times 0-6=1.5$$

Multiply 12 and \frac{1}{4} to get 3.

$$F-3-15\times 0-6=1.5$$

Multiply 15 and 0 to get 0.

$$F-3-0-6=1.5$$

Add 6 to both sides.

$$F-3-0=1.5+6$$

Add 1.5 and 6 to get 7.5.

$$F-3-0=7.5$$

Add 0 to both sides.

$$F-3=7.5+0$$

Add 7.5 and 0 to get 7.5.

$$F-3=7.5$$

Add 3 to both sides.

$$F=7.5+3$$

Add 7.5 and 3 to get 10.5.

$$F=10.5$$

The system is now solved.

$$F=10.5 \mu =\frac{1}{4}$$