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Solve for A, B, C
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C=\frac{2^{2}-2^{2}}{2}
Consider the third equation. Insert the known values of variables into the equation.
C=\frac{4-2^{2}}{2}
Calculate 2 to the power of 2 and get 4.
C=\frac{4-4}{2}
Calculate 2 to the power of 2 and get 4.
C=\frac{0}{2}
Subtract 4 from 4 to get 0.
C=0
Zero divided by any non-zero number gives zero.
A=1 B=2 C=0
The system is now solved.