Solve {l}{A=(B+b/2)*h}{b=23-3}{B=b^2+3-1}{h=20}

$$\left. \begin{array} { l } { A = ( \frac { B + b } { 2 } ) \times h } \\ { b = 23 - 3 } \\ { B = b ^ { 2 } + 3 - 1 } \\ { h = 20 } \end{array} \right.$$

Solve for A, B, b, h

$$A=4220$$

$$B=402$$

$$b=20$$

$$h=20$$

Solution Steps

Consider the second equation. Subtract 3 from 23 to get 20.

$$b=20$$

Consider the third equation. Insert the known values of variables into the equation.

$$B=20^{2}+3-1$$

Calculate 20 to the power of 2 and get 400.

$$B=400+3-1$$

Add 400 and 3 to get 403.

$$B=403-1$$

Subtract 1 from 403 to get 402.

$$B=402$$

Consider the first equation. Insert the known values of variables into the equation.

$$A=\frac{402+20}{2}\times 20$$

Add 402 and 20 to get 422.

$$A=\frac{422}{2}\times 20$$

Divide 422 by 2 to get 211.

$$A=211\times 20$$

Multiply 211 and 20 to get 4220.

$$A=4220$$

The system is now solved.

$$A=4220 B=402 b=20 h=20$$