Solve {l}{7*8-(31-61)}{(1-2)^6}

$$\left. \begin{array} { l } { 7 \cdot 8 - ( 31 - 61 ) } \\ { ( 1 - 2 ) ^ { 6 } } \end{array} \right.$$

Sort

$$1,86$$

Solution Steps

Multiply 7 and 8 to get 56.

$$sort(56-\left(31-61\right),\left(1-2\right)^{6})$$

Subtract 61 from 31 to get -30.

$$sort(56-\left(-30\right),\left(1-2\right)^{6})$$

The opposite of -30 is 30.

$$sort(56+30,\left(1-2\right)^{6})$$

Add 56 and 30 to get 86.

$$sort(86,\left(1-2\right)^{6})$$

Subtract 2 from 1 to get -1.

$$sort(86,\left(-1\right)^{6})$$

Calculate -1 to the power of 6 and get 1.

$$sort(86,1)$$

To sort the list, start from a single element 86.

$$86$$

Insert 1 to the appropriate location in the new list.

$$1,86$$

Evaluate

$$86,\ 1$$