Solve for a, c
a=\frac{3}{5}=0.6
c=3
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5a+4=7
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
5a=7-4
Subtract 4 from both sides.
5a=3
Subtract 4 from 7 to get 3.
a=\frac{3}{5}
Divide both sides by 5.
7c-2c=15
Consider the second equation. Subtract 2c from both sides.
5c=15
Combine 7c and -2c to get 5c.
c=\frac{15}{5}
Divide both sides by 5.
c=3
Divide 15 by 5 to get 3.
a=\frac{3}{5} c=3
The system is now solved.
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