Solve {l}{6s+t=3s+8}{4s-1=4}

$$\left. \begin{array} { l } { 6 s + t = 3 s + 8 } \\ { 4 s - 1 = 4 } \end{array} \right.$$

Solve for s, t

$$t = \frac{17}{4} = 4\frac{1}{4} = 4.25$$

$$s = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

Solution Steps

Consider the second equation. Add 1 to both sides.

$$4s=4+1$$

Add 4 and 1 to get 5.

$$4s=5$$

Divide both sides by 4.

$$s=\frac{5}{4}$$

Consider the first equation. Insert the known values of variables into the equation.

$$6\times \frac{5}{4}+t=3\times \frac{5}{4}+8$$

Multiply 6 and \frac{5}{4} to get \frac{15}{2}.

$$\frac{15}{2}+t=3\times \frac{5}{4}+8$$

Multiply 3 and \frac{5}{4} to get \frac{15}{4}.

$$\frac{15}{2}+t=\frac{15}{4}+8$$

Add \frac{15}{4} and 8 to get \frac{47}{4}.

$$\frac{15}{2}+t=\frac{47}{4}$$

Subtract \frac{15}{2} from both sides.

$$t=\frac{47}{4}-\frac{15}{2}$$

Subtract \frac{15}{2} from \frac{47}{4} to get \frac{17}{4}.

$$t=\frac{17}{4}$$

The system is now solved.

$$s=\frac{5}{4} t=\frac{17}{4}$$