Solve {l}{49-3h=8(5)}{-6a+5h=-13(3)}

$$\left. \begin{array} { l } { 49 - 3 h = 8 ( 5 ) } \\ { - 6 a + 5 h = - 13 ( 3 ) } \end{array} \right.$$

Solve for h, a

$$h=3$$

$$a=9$$

Solution Steps

Consider the first equation. Multiply 8 and 5 to get 40.

$$49-3h=40$$

Subtract 49 from both sides.

$$-3h=40-49$$

Subtract 49 from 40 to get -9.

$$-3h=-9$$

Divide both sides by -3.

$$h=\frac{-9}{-3}$$

Divide -9 by -3 to get 3.

$$h=3$$

Consider the second equation. Insert the known values of variables into the equation.

$$-6a+5\times 3=-13\times 3$$

Multiply 5 and 3 to get 15.

$$-6a+15=-13\times 3$$

Multiply -13 and 3 to get -39.

$$-6a+15=-39$$

Subtract 15 from both sides.

$$-6a=-39-15$$

Subtract 15 from -39 to get -54.

$$-6a=-54$$

Divide both sides by -6.

$$a=\frac{-54}{-6}$$

Divide -54 by -6 to get 9.

$$a=9$$

The system is now solved.

$$h=3 a=9$$