Solve for y, a
y=10
a=-1
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-12-\left(-y\right)=-2
Consider the first equation. Multiply 4 and -3 to get -12.
-12+y=-2
The opposite of -y is y.
y=-2+12
Add 12 to both sides.
y=10
Add -2 and 12 to get 10.
5a=15-20
Consider the second equation. Subtract 20 from both sides.
5a=-5
Subtract 20 from 15 to get -5.
a=\frac{-5}{5}
Divide both sides by 5.
a=-1
Divide -5 by 5 to get -1.
y=10 a=-1
The system is now solved.
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