Solve {l}{3y+x=3}{3^2-y=0}

$$\left. \begin{array} { l } { 3 y + x = 3 } \\ { 3 ^ { 2 } - y = 0 } \end{array} \right.$$

Solve for y, x

$$x=-24$$

$$y=9$$

Solution Steps

Consider the second equation. Calculate 3 to the power of 2 and get 9.

$$9-y=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$-y=-9$$

Divide both sides by -1.

$$y=\frac{-9}{-1}$$

Fraction \frac{-9}{-1} can be simplified to 9 by removing the negative sign from both the numerator and the denominator.

$$y=9$$

Consider the first equation. Insert the known values of variables into the equation.

$$3\times 9+x=3$$

Multiply 3 and 9 to get 27.

$$27+x=3$$

Subtract 27 from both sides.

$$x=3-27$$

Subtract 27 from 3 to get -24.

$$x=-24$$

The system is now solved.

$$y=9 x=-24$$