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3x=7+6
Consider the first equation. Add 6 to both sides.
3x=13
Add 7 and 6 to get 13.
x=\frac{13}{3}
Divide both sides by 3.
3y-6=\frac{13}{3}
Consider the second equation. Insert the known values of variables into the equation.
3y=\frac{13}{3}+6
Add 6 to both sides.
3y=\frac{31}{3}
Add \frac{13}{3} and 6 to get \frac{31}{3}.
y=\frac{\frac{31}{3}}{3}
Divide both sides by 3.
y=\frac{31}{3\times 3}
Express \frac{\frac{31}{3}}{3} as a single fraction.
y=\frac{31}{9}
Multiply 3 and 3 to get 9.
x=\frac{13}{3} y=\frac{31}{9}
The system is now solved.