Solve for x
x=\frac{2\left(y-3\right)}{3}
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3x+6=2y
Add 2y to both sides. Anything plus zero gives itself.
3x=2y-6
Subtract 6 from both sides.
\frac{3x}{3}=\frac{2y-6}{3}
Divide both sides by 3.
x=\frac{2y-6}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{2y}{3}-2
Divide -6+2y by 3.
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