Solve {l}{3x+4=3}{2x+y=1}

$$\left. \begin{array} { l } { 3 x + 4 = 3 } \\ { 2 x + y = 1 } \end{array} \right.$$

Solve for x, y

$$x=-\frac{1}{3}\approx -0.333333333$$

$$y = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$3x=3-4$$

Subtract 4 from 3 to get -1.

$$3x=-1$$

Divide both sides by 3.

$$x=-\frac{1}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$2\left(-\frac{1}{3}\right)+y=1$$

Multiply 2 and -\frac{1}{3} to get -\frac{2}{3}.

$$-\frac{2}{3}+y=1$$

Add \frac{2}{3} to both sides.

$$y=1+\frac{2}{3}$$

Add 1 and \frac{2}{3} to get \frac{5}{3}.

$$y=\frac{5}{3}$$

The system is now solved.

$$x=-\frac{1}{3} y=\frac{5}{3}$$