Solve {l}{3x+2=4x+9}{m+4-3m=4+12m}

$$\left. \begin{array} { l } { 3 x + 2 = 4 x + 9 } \\ { m + 4 - 3 m = 4 + 12 m } \end{array} \right.$$

Solve for x, m

$$x=-7$$

$$m=0$$

Solution Steps

Consider the first equation. Subtract 4x from both sides.

$$3x+2-4x=9$$

Combine 3x and -4x to get -x.

$$-x+2=9$$

Subtract 2 from both sides.

$$-x=9-2$$

Subtract 2 from 9 to get 7.

$$-x=7$$

Divide both sides by -1.

$$x=-7$$

Consider the second equation. Combine m and -3m to get -2m.

$$-2m+4=4+12m$$

Subtract 12m from both sides.

$$-2m+4-12m=4$$

Combine -2m and -12m to get -14m.

$$-14m+4=4$$

Subtract 4 from both sides.

$$-14m=4-4$$

Subtract 4 from 4 to get 0.

$$-14m=0$$

Divide both sides by -14. Zero divided by any non-zero number gives zero.

$$m=0$$

The system is now solved.

$$x=-7 m=0$$