Solve {l}{3a^3+6a^2-2a^2}{+6a^2}

$$\left. \begin{array} { l } { 3 a ^ { 3 } + 6 a ^ { 2 } - 2 a ^ { 2 } } \\ { + 6 a ^ { 2 } } \end{array} \right.$$

Evaluate

$$\left(3a+10\right)a^{2}$$

Solution Steps

Combine 6a^{2} and -2a^{2} to get 4a^{2}.

$$3a^{3}+4a^{2}+6a^{2}$$

Combine 4a^{2} and 6a^{2} to get 10a^{2}.

$$3a^{3}+10a^{2}$$

Factor

$$\left(3a+10\right)a^{2}$$

Solution Steps

Factor out a^{2}.

$$a^{2}\left(3a+10\right)$$

Consider 3a+6-2+6. Multiply and combine like terms.

$$3a+10$$

Rewrite the complete factored expression.

$$a^{2}\left(3a+10\right)$$