Solve {l}{3(x-5)=24}{4/5(c+12)=0}

$$\left. \begin{array} { l } { 3 ( x - 5 ) = 24 } \\ { \frac { 4 } { 5 } ( c + 12 ) = 0 } \end{array} \right.$$

Solve for x, c

$$x=13$$

$$c=-12$$

Solution Steps

Consider the first equation. Divide both sides by 3.

$$x-5=\frac{24}{3}$$

Divide 24 by 3 to get 8.

$$x-5=8$$

Add 5 to both sides.

$$x=8+5$$

Add 8 and 5 to get 13.

$$x=13$$

Consider the second equation. Multiply both sides by \frac{5}{4}, the reciprocal of \frac{4}{5}. Anything times zero gives zero.

$$c+12=0$$

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$c=-12$$

The system is now solved.

$$x=13 c=-12$$