Solve {l}{3*(-1)^3+2*(-1)^2}{+2*(-1)+3}

$$\left. \begin{array} { l } { 3 \cdot ( - 1 ) ^ { 3 } + 2 \cdot ( - 1 ) ^ { 2 } } \\ { + 2 \cdot ( - 1 ) + 3 } \end{array} \right.$$

Evaluate

$$0$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$3\left(-1\right)+2\left(-1\right)^{2}+2\left(-1\right)+3$$

Multiply 3 and -1 to get -3.

$$-3+2\left(-1\right)^{2}+2\left(-1\right)+3$$

Calculate -1 to the power of 2 and get 1.

$$-3+2\times 1+2\left(-1\right)+3$$

Multiply 2 and 1 to get 2.

$$-3+2+2\left(-1\right)+3$$

Add -3 and 2 to get -1.

$$-1+2\left(-1\right)+3$$

Multiply 2 and -1 to get -2.

$$-1-2+3$$

Subtract 2 from -1 to get -3.

$$-3+3$$

Add -3 and 3 to get 0.

$$0$$

Factor

$$0$$