Solve {l}{3+2t-3=c}{7-4t=4}

$$\left. \begin{array} { l } { 3 + 2 t - 3 = c } \\ { 7 - 4 t = 4 } \end{array} \right.$$

Solve for t, c

$$t=\frac{3}{4}=0.75$$

$$c = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Solution Steps

Consider the second equation. Subtract 7 from both sides.

$$-4t=4-7$$

Subtract 7 from 4 to get -3.

$$-4t=-3$$

Divide both sides by -4.

$$t=\frac{-3}{-4}$$

Fraction \frac{-3}{-4} can be simplified to \frac{3}{4} by removing the negative sign from both the numerator and the denominator.

$$t=\frac{3}{4}$$

Consider the first equation. Insert the known values of variables into the equation.

$$3+2\times \frac{3}{4}-3=c$$

Multiply 2 and \frac{3}{4} to get \frac{3}{2}.

$$3+\frac{3}{2}-3=c$$

Add 3 and \frac{3}{2} to get \frac{9}{2}.

$$\frac{9}{2}-3=c$$

Subtract 3 from \frac{9}{2} to get \frac{3}{2}.

$$\frac{3}{2}=c$$

Swap sides so that all variable terms are on the left hand side.

$$c=\frac{3}{2}$$

The system is now solved.

$$t=\frac{3}{4} c=\frac{3}{2}$$