Solve for a, b, c
a=1
b=-21
c=98
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c=-225a-15b+8
Solve 225a+15b+c=8 for c.
256a+16b-225a-15b+8=18 289a+17b-225a-15b+8=30
Substitute -225a-15b+8 for c in the second and third equation.
b=-31a+10 a=\frac{11}{32}-\frac{1}{32}b
Solve these equations for b and a respectively.
a=\frac{11}{32}-\frac{1}{32}\left(-31a+10\right)
Substitute -31a+10 for b in the equation a=\frac{11}{32}-\frac{1}{32}b.
a=1
Solve a=\frac{11}{32}-\frac{1}{32}\left(-31a+10\right) for a.
b=-31+10
Substitute 1 for a in the equation b=-31a+10.
b=-21
Calculate b from b=-31+10.
c=-225-15\left(-21\right)+8
Substitute -21 for b and 1 for a in the equation c=-225a-15b+8.
c=98
Calculate c from c=-225-15\left(-21\right)+8.
a=1 b=-21 c=98
The system is now solved.
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