Solve for x, y, z
x=2
y=0
z=-1
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y=2x+z-3
Solve 2x-y+z=3 for y.
x+2\left(2x+z-3\right)+z=1 4x+2\left(2x+z-3\right)-3z=11
Substitute 2x+z-3 for y in the second and third equation.
x=-\frac{3}{5}z+\frac{7}{5} z=8x-17
Solve these equations for x and z respectively.
z=8\left(-\frac{3}{5}z+\frac{7}{5}\right)-17
Substitute -\frac{3}{5}z+\frac{7}{5} for x in the equation z=8x-17.
z=-1
Solve z=8\left(-\frac{3}{5}z+\frac{7}{5}\right)-17 for z.
x=-\frac{3}{5}\left(-1\right)+\frac{7}{5}
Substitute -1 for z in the equation x=-\frac{3}{5}z+\frac{7}{5}.
x=2
Calculate x from x=-\frac{3}{5}\left(-1\right)+\frac{7}{5}.
y=2\times 2-1-3
Substitute 2 for x and -1 for z in the equation y=2x+z-3.
y=0
Calculate y from y=2\times 2-1-3.
x=2 y=0 z=-1
The system is now solved.
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Limits
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