Solve {l}{2x(-393.5)+3*(-285.8)}{+1559.8}

$$\left. \begin{array} { l } { 2 x ( - 393.5 ) + 3 \times ( - 285.8 ) } \\ { + 1559.8 } \end{array} \right.$$

Evaluate

$$702.4-787x$$

Solution Steps

Multiply 2 and -393.5 to get -787.

$$-787x+3\left(-285.8\right)+1559.8$$

Multiply 3 and -285.8 to get -857.4.

$$-787x-857.4+1559.8$$

Add -857.4 and 1559.8 to get 702.4.

$$-787x+702.4$$

Differentiate w.r.t. x

$$-787$$

Steps Using Derivative Rule for Sum

Multiply 2 and -393.5 to get -787.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-787x+3\left(-285.8\right)+1559.8)$$

Multiply 3 and -285.8 to get -857.4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-787x-857.4+1559.8)$$

Add -857.4 and 1559.8 to get 702.4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-787x+702.4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-787x^{1-1}$$

Subtract 1 from 1.

$$-787x^{0}$$

For any term t except 0, t^{0}=1.

$$-787$$