Solve {l}{2x^2+y=3}{x+2=7}

$$\left. \begin{array} { l } { 2 x ^ { 2 } + y = 3 } \\ { x + 2 = 7 } \end{array} \right.$$

Solve for x, y

$$x=5$$

$$y=-47$$

Solution Steps

Consider the second equation. Subtract 2 from both sides.

$$x=7-2$$

Subtract 2 from 7 to get 5.

$$x=5$$

Consider the first equation. Insert the known values of variables into the equation.

$$2\times 5^{2}+y=3$$

Calculate 5 to the power of 2 and get 25.

$$2\times 25+y=3$$

Multiply 2 and 25 to get 50.

$$50+y=3$$

Subtract 50 from both sides.

$$y=3-50$$

Subtract 50 from 3 to get -47.

$$y=-47$$

The system is now solved.

$$x=5 y=-47$$