Solve {l}{2x+4=60}{5x+3d=46}

$$\left. \begin{array} { l } { 2 x + 4 = 60 } \\ { 5 x + 3 d = 46 } \end{array} \right.$$

Solve for x, d

$$x=28$$

$$d = -\frac{94}{3} = -31\frac{1}{3} \approx -31.333333333$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$2x=60-4$$

Subtract 4 from 60 to get 56.

$$2x=56$$

Divide both sides by 2.

$$x=\frac{56}{2}$$

Divide 56 by 2 to get 28.

$$x=28$$

Consider the second equation. Insert the known values of variables into the equation.

$$5\times 28+3d=46$$

Multiply 5 and 28 to get 140.

$$140+3d=46$$

Subtract 140 from both sides.

$$3d=46-140$$

Subtract 140 from 46 to get -94.

$$3d=-94$$

Divide both sides by 3.

$$d=-\frac{94}{3}$$

The system is now solved.

$$x=28 d=-\frac{94}{3}$$