Solve {l}{2}{7/8}{7/7-1/2}

$$\left. \begin{array} { l } { 2 } \\ { \frac { 7 } { 8 } } \\ { \frac { 7 } { 7 } - \frac { 1 } { 2 } } \end{array} \right.$$

Sort

$$\frac{1}{2},\frac{7}{8},2$$

Solution Steps

Divide 7 by 7 to get 1.

$$sort(2,\frac{7}{8},1-\frac{1}{2})$$

Convert 1 to fraction \frac{2}{2}.

$$sort(2,\frac{7}{8},\frac{2}{2}-\frac{1}{2})$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$sort(2,\frac{7}{8},\frac{2-1}{2})$$

Subtract 1 from 2 to get 1.

$$sort(2,\frac{7}{8},\frac{1}{2})$$

Convert decimal numbers in the list 2,\frac{7}{8},\frac{1}{2} to fractions.

$$2,\frac{7}{8},\frac{1}{2}$$

Least common denominator of the numbers in the list 2,\frac{7}{8},\frac{1}{2} is 8. Convert numbers in the list to fractions with denominator 8.

$$\frac{16}{8},\frac{7}{8},\frac{4}{8}$$

To sort the list, start from a single element \frac{16}{8}.

$$\frac{16}{8}$$

Insert \frac{7}{8} to the appropriate location in the new list.

$$\frac{7}{8},\frac{16}{8}$$

Insert \frac{4}{8} to the appropriate location in the new list.

$$\frac{4}{8},\frac{7}{8},\frac{16}{8}$$

Replace the obtained fractions with the initial values.

$$\frac{1}{2},\frac{7}{8},2$$

Evaluate

$$2,\ \frac{7}{8},\ \frac{1}{2}$$