Solve {l}{2^{2}+3+4^2}{+5^2+6^2}{+7^2}

$$\left. \begin{array} { l } { 2 ^ { 2 } + 3 + 4 ^ { 2 } } \\ { + 5 ^ { 2 } + 6 ^ { 2 } } \\ { + 7 ^ { 2 } } \end{array} \right.$$

Evaluate

$$133$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4+3+4^{2}+5^{2}+6^{2}+7^{2}$$

Add 4 and 3 to get 7.

$$7+4^{2}+5^{2}+6^{2}+7^{2}$$

Calculate 4 to the power of 2 and get 16.

$$7+16+5^{2}+6^{2}+7^{2}$$

Add 7 and 16 to get 23.

$$23+5^{2}+6^{2}+7^{2}$$

Calculate 5 to the power of 2 and get 25.

$$23+25+6^{2}+7^{2}$$

Add 23 and 25 to get 48.

$$48+6^{2}+7^{2}$$

Calculate 6 to the power of 2 and get 36.

$$48+36+7^{2}$$

Add 48 and 36 to get 84.

$$84+7^{2}$$

Calculate 7 to the power of 2 and get 49.

$$84+49$$

Add 84 and 49 to get 133.

$$133$$

Factor

$$7\times 19$$