Solve {l}{15^{2}+16^{2}+17^2}{11^2+19^2}{+20^2}

$$\left. \begin{array} { l } { 15 ^ { 2 } + 16 ^ { 2 } + 17 ^ { 2 } } \\ { 11 ^ { 2 } + 19 ^ { 2 } } \\ { + 20 ^ { 2 } } \end{array} \right.$$

Sort

$$400,482,770$$

Solution Steps

Calculate 15 to the power of 2 and get 225.

$$sort(225+16^{2}+17^{2},11^{2}+19^{2},20^{2})$$

Calculate 16 to the power of 2 and get 256.

$$sort(225+256+17^{2},11^{2}+19^{2},20^{2})$$

Add 225 and 256 to get 481.

$$sort(481+17^{2},11^{2}+19^{2},20^{2})$$

Calculate 17 to the power of 2 and get 289.

$$sort(481+289,11^{2}+19^{2},20^{2})$$

Add 481 and 289 to get 770.

$$sort(770,11^{2}+19^{2},20^{2})$$

Calculate 11 to the power of 2 and get 121.

$$sort(770,121+19^{2},20^{2})$$

Calculate 19 to the power of 2 and get 361.

$$sort(770,121+361,20^{2})$$

Add 121 and 361 to get 482.

$$sort(770,482,20^{2})$$

Calculate 20 to the power of 2 and get 400.

$$sort(770,482,400)$$

To sort the list, start from a single element 770.

$$770$$

Insert 482 to the appropriate location in the new list.

$$482,770$$

Insert 400 to the appropriate location in the new list.

$$400,482,770$$

Evaluate

$$770,\ 482,\ 400$$